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  1. #1
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    Middlebrook extra element theorem

    I am going through Middlebrook and Voperians work on the extra element theorem. I succeed to prove the extra element theorem with Z open, Z short, gm-->0 (dependent current source), A-->0 (dependent voltage source).

    What I can't seem to figure out is how to prove the EET for dependent sources with gm --> infinity or A--> infinity. Does anyone have a proof?

    For reference the EET for dependent sources with gm -->∞ and A -->∞ is:

    H(s) = (H|gm=inf) * (1 + ( 1/(gm*Tn) ) / (1 + (1/(gm*Td) )

    or

    H(s) = (H|A=inf) * (1 + (1/(A*Tn) ) / (1 + (1/(A*Td) )

    Edit: I used the following reference from R W Erickson site which shows how the EET is proved. But it is only for impedance. Would be great if someone can outline a similar proof for dependent sources with gain set to infinity:

    http://ecee.colorado.edu/~ecen5807/l..._5807_out1.pdf
    Last edited by powerelec; 5th February 2014 at 15:34.

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  2. #2
    Junior Member level 2
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    Re: Middlebrook extra element theorem

    Anyone familiar with Middlebrook EET and NEET techniques? Would be great to get a discussion on these going..



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