[SOLVED] The difference between "initial" and "always"

u24c02 said:

Hi i want to know following verilog that
2. The difference between blocking assinment and nonblocking assignment.

The Verilog language has two forms of the procedural assignment statement: blocking and non-blocking. The two are distinguished by the = and <= assignment operators. The blocking assignment statement (= operator) acts much like in traditional programming languages. The whole statement is done before control passes on to the next statement. The non-blocking (<= operator) evaluates all the right-hand sides for the current time unit and assigns the left-hand sides at the end of the time unit. For example, the following Verilog program

// testing blocking and non-blocking assignment

module blocking;
reg [0:7] A, B;
initial begin: init1
A = 3;
#1 A = A + 1; // blocking procedural assignment
B = A + 1;

$display("Blocking: A= %b B= %b", A, B ); A = 3;
#1 A <= A + 1; // non-blocking procedural assignment
B <= A + 1;
#1 $display("Non-blocking: A= %b B= %b", A, B );
end
endmodule

produces the following output:
Blocking: A= 00000100 B= 00000101
Non-blocking: A= 00000100 B= 00000100

The effect is for all the non-blocking assignments to use the old values of the variables at the beginning of the current time unit and to assign the registers new values at the end of the current time unit. This reflects how register transfers occur in some hardware systems.
blocking procedural assignment is used for combinational logic and non-blocking procedural assignment for sequential

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