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class AB diode biasing

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amad_nugent

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Can someone explain why the ratio of junction area of the output devices to the biasing diodes come into play? why its important?

thanks a lot
 

Since the diode is in parallel with the base emitter, they have the same voltage across them. Higher cross sectional area for a given voltage produces higher current.
 

why does Quiescent current= n*Ibias?
n is the ratio of the diode size to the transistor size
 

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