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integration of (1/dx) - please help

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Aya2002

Aya2002

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integration of 1/dx

Hi Friends,

i faced this problem which is the integration of 1/dx !!!! would some body help me please?

∫(1/dx)=?

thanks
 

integration of 1/dx

Hi Aya,

" ∫(1/dx) " is a combination of symbols that has no mathematical meaning.
A valid expression would be " ∫(1/x)dx " for example.

Regards

Z
 

    Aya2002

    Aya2002

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i think it is a differential equation !!!
 

Hi,
If it is ∫1/x dx the result is log(x)+cte
 

AdvaRes said:
Hi,
If it is ∫1/x dx the result is log(x)+cte
Click to expand...

but it is not ∫1/x dx

it is ∫1/dx
 

That doesn't seem like a valid integral. Where are you getting this from?
 

hi friend

the original equation is

dt=c/dx

so, i see it is a differential equation:!:
 

Aya2002 said:
the original equation is
dt=c/dx
so, i see it is a differential equation:!:
Click to expand...

Please, re-read the original equation.

dt = c · dx is a differential equation.

dt = c / dx is nothing.
 

    Aya2002

    Aya2002

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how it is nothing?

would you explain please?
 

Zorro explained it very well. This combination of math symbols just has no meaning at all. Your question is similar to ask for "... how can I evaluate 5+*/7= ?..."
 

Hi,

Huh !

Actually I think that you lost something during your simplification or you are dealing with partial derivation.

Could you please through more light on the problem by telling us from where you picked up this function or how did you arrive there?

If you are calculating c=dt.dx the relation ∫∫dx dt has a sens.
 

    Aya2002

    Aya2002

    Points: 2
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AdvaRes said:
Hi,

Huh !

Actually I think that you lost something during your simplification or you are dealing with partial derivation.

Could you please through more light on the problem by telling us from where you picked up this function or how did you arrive there?

If you are calculating c=dt.dx the relation ∫∫dx dt has a sens.
Click to expand...

now the result is clear from your answer

thanks
 

Aya2002 said:
AdvaRes said:
Hi,

Huh !
If you are calculating c=dt.dx the relation ∫∫dx dt has a sens.
Click to expand...

now the result is clear from your answer
Click to expand...

MM I'm taking DiffEq and Leibniz Notation is giving me a headache this somewhat resembles it
∫(1/dx) has no meaning but ∫dt does because dt = c/dx If they're supposed to be equivalent (i.e LHS == RHS) how one doesn't make sense but the other does, I thought dx was pure notational
 

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