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I've been a nice guy and done it right for the thread starter
The answer is that all positive voltage goes zero. All negative voltages between 0 and -0.6V also goes practically zero. All voltages more negative than -0.6V will be the input voltage added by aproximately 0.6V.
Exactly how the waveform will look depends on input voltage, value of R, and the characteristic of the diode.
This is a half wave rectifier that conducts in the negative half cycle of the input. Actual output waveform will start from a phase angle dependant on the cut-in voltage of the diode and the peak value of the output voltage is dependant on the maximum forward votage. It will start conducting during time corresponding to input < -|Vcutin| and the peak output is -|Vin-Vmax|
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