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    [SOLVED] Why divide by N (length of input sequence) during IDFT?

    Hi folk During DFT of a input sequence of length N, we find X(k). X(k) = <x[n], e[k, n]> where e(k, n)=[e-2kπ/N e-2kπ*2/N e-2kπ*3/N ... e-2kπ*(N-1)/N ]. For each value of k, I get a coefficient. Similarly I got coefficients for all basis in the vector space. Now to reconstruct the original...

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