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Type: Posts; User: _Eduardo_

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  1. Replies
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    Closed: Re: Second order RLC circuit

    Because it's an inductor. The voltage at its terminals is not defined by the current but it derivative.
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    Closed: Re: Second order RLC circuit

    Of course, but has no effect on the current derivative at t=0+


    Just think on the standard RLC: Vc + Vr + VL = 0

    But VL = L I' = L Vr'/R

    then Vc + Vr + (L/R)Vr' = 0

    At t=0+ ...
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    Closed: Re: Second order RLC circuit

    You start well:

    At t=0+

    Il = -Ix = 2A
    Vc = 16V
    Vx = -24V
    Vr = 16V
  4. Replies
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    Closed: Re: Second order RLC circuit

    Hi.

    At t=0+ Vc=16V and I=2A then V_R12+V_R8 = (12+8)*2 = 40V ==> VL = Vc-(V_R12+V_R8) = 16 - 40 = -24V
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    Closed: Re: Second order RLC circuit

    At t=0+

    Vc=16V ; I_L=I=16/8=2A
    and

    L I' + (R12+R8) I = Vc ---> L I_0' + (R12+R8) I_0 = Vc_0 ---> I_0' = 16 - 20*2 = -24A/s

    Then V_R_0' = R8 I_0' = 8*(-24) = -192V/s
  6. Replies
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    Closed: Re: solving differential equations help

    Hint:

    xy' - y = x^2 (y/x)'
    and

    y' -3x^2 y = (y e^(-x^3))' e^(x^3)



    Then
  7. Replies
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    Closed: Re: Op-amp circuit analysis

    In such process, dependant-sources cannot be passivated.
  8. Replies
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    657

    Closed: Re: Encoder Reading Problem

    Upload your code.
  9. Replies
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    1,338

    Closed: Re: RL circuit simulation problems in proteus

    Diode is not a switch, use a controlled switch like a relay.

    148491
  10. Replies
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    Closed: Re: Which Law is this ?

    B + !BA = B(1+A) + !BA = B + BA + !BA = B + (B+!B)A = B + A

    But is more easy to see with kmap.
  11. Replies
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    Closed: Re: I Need help on this K-Map

    Yes, you are using a curious way to assign the 1's in the kmap.

    Perhaps a wrong conversion decimal to binary.
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    Closed: Re: Resistor and current calculation

    Do you think that the same circuit is used for a current of 100mA than for a current of 100A?


    For a motor you not need any voltage converter, it's enough a simple pulse width regulator.
    ...
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    Closed: Re: Resistor and current calculation

    Keep in mind https://www.aliexpress.com/store/product/DC-DC-Buck-Converter-4V-40V-1-2V-36V-8A-100W-Step-Down-Voltage-Power-Module/1414081_32760917735.html


    But you should have started with: ...
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    Closed: Re: Resistor and current calculation

    Look for a MC34063 online calculator (ie https://www.electronicproducts.com/DC-DC_Circuit_Calculator.aspx )

    But in the datasheets you have circuits diagrams for many configurations and...
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    Closed: Re: Resistor and current calculation

    It's no true "but also reduces the current to zero" , that equation is valid only when Iout=0

    When Iout<>0 --> Vout=Vin*R2/(R1+R2) - Iout (R1//R2)


    The voltage divider is not suitable for...
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    Closed: Re: Chunt resistor measurement

    If you have a multimeter Agilent U1242B you cannot check in range of mΩ. That 1.6Ω is the resistance of contact+probe_wire+Rshunt


    Look for another instrument or a Kelvin bridge.
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    Closed: Re: Rc circuit with Iin1 and Iin2

    Is the circuit behavior after a certain excitation.
  18. Replies
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    Closed: Re: Rc circuit with Iin1 and Iin2

    But that picture isn't the response of your RC circuit with an ideal current source. Is the response with a voltage source + diode bridge.
  19. Closed: Re: how to extract a function from an integral?

    \displaystyle\int_{0}^{\infty}g(x)\text{d}x = \text{constant} \;\; \forall \; g(x)

    Please, write the equation properly.
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    Closed: Re: Transfer function of Multi variable system

    My version is 2008b.

    The Bode plot is

    140250


    ------------------------------------

    For versions lower than 2008b try this function:
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    Closed: Re: Transfer function of Multi variable system

    I have only a basic knowledge of Matlab (and english) but you can write:


    % Data
    Rs = 50 ; R1 = 0.075 ; R2 = 0.23 ; % ohms
    R3 = 0.11 ; R4 = 0.032 ; % ohms
    RL = 100 ; ...
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    Closed: Re: Simple Mesh or Node circuit?

    It's OK

    But you could avoid a 3x3 system by separating the R_6ohm because does not affect the others.



    Also you could write node equations -> only one unknown V(1/4+1/8+1/2) = 48/4 ==> V =...
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    Closed: Re: Thevenise circuit problem

    Your method and results are correct (unless the rounding error)

    The exact values are: Rth = 448/89 ≈ 5.033707865 , Vth = 200/89 ≈ 2.247191011
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    Closed: Re: Tricky nodal analysis

    Just write the node equations following the rules:


    (1/R1+1/R2+1/R4)V1 - (1/R2+1/R4)V2 = E1/R1 - E2/R4 - I1
    -(1/R2+1/R4)V1 + (1/R2+1/R3+1/R4)V2 = E2/R4 + I1 - I2
  25. Replies
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    Closed: Re: two dimension array problem

    Microcontroller? Compiler?
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