How do you convert rad^2/Hz to dBc/Hz ?
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Ok, it's 10 log (rad^2/Hz)^2 / 2
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How do you convert rad^2/Hz to dBc/Hz ?
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Ok, it's 10 log (rad^2/Hz)^2 / 2
in general, a measure in dB is 10 log (A/reference A)
so things like voltage would be 10 log (voltage/reference voltage)
and things like power would be 20 log(power/power reference)
you must use a reference (or at least an implied reference) because you cannot take the log of a unit
log (volts) or log(meter) cannot be done - you can only take the log of a number.
What is the c in dBc?
rad is a dimensionless angle measure - that is, rad is an angle without a unit.
i do not know what rad^2/Hz is
it makes no sense to me to convert an angle to a dBc
please provide context for the question
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i don't think so
you cannot take the log of a unit
please provide context - what are you doing that brought up this question?
Phase Noise calculations - it's all normalized to per hz so it's fine.