Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

conversation Gain ADS

Status
Not open for further replies.

laperla

Full Member level 4
Joined
Oct 17, 2009
Messages
191
Helped
2
Reputation
4
Reaction score
3
Trophy points
1,298
Activity points
2,364
conversion Gain ADS

Hi

How can I obtain conversation Gain in the ADS?
 
Last edited:

You can't. You might be able to get conversion gain.
 

why?
How can I get conversation gain?
 

In the data control, you can set two marks, then the conversion gain is Mark1-mark2, edit a equation.
 

ohhhh excuse me. that's terrible mistake
 

plzzz help me to calculate it
 

plzzz help me to calculate it
To calculate the conversion gain is very simple.
Conversion gain of a mixer=Output Level at RF/IF Signal(dBm)-Input Level at RF/IF Signal(dBm)
So, simply converted dignals are extracted from each other.
For instance..
You have 1GHz LO frequency, 100MHz RF signal with -10dBm and output level is +10dBm at 900MHz and 1100MHz.
You should observe the spectrum at 900MHz and 1100MHz.And then find the power levels and compare with which is suitable for you.
That's it..
 
there are many methods to calculate the conversion gain in ADS.
1.such as for mixer, see 111.jpg.
2.for data process, see 112.jpg, then edit equation: CG=Mark1-Mark2.
for syntax problem, you can check ads help file.
3. You can also add I probe and V probe, then power is I*V, then edit equation to calculate two power difference.
 

Attachments

  • 111.JPG
    111.JPG
    9.9 KB · Views: 90
  • 112.JPG
    112.JPG
    11.5 KB · Views: 76
Re: conversion Gain ADS

thanks for reply


I want to know why you write {-1,1}?in some cases write that {1,1} or {0,1} what's mean?

another problem is that I want to draw the curve, not just one measure


---------- Post added at 18:05 ---------- Previous post was at 17:57 ----------

You have 1GHz LO frequency, 100MHz RF signal with -10dBm and output level is +10dBm at 900MHz and 1100MHz.
You should observe the spectrum at 900MHz and 1100MHz.And then find the power levels and compare with which is suitable for you.
That's it..
dear Bigboss
I found my project from this forum I don't have any idea I'm amature in this field just want to practice and find that how I can design gilbert cell
 
Last edited:

Re: conversion Gain ADS

thanks for reply
I want to know why you write {-1,1}?in some cases write that {1,1} or {0,1} what's mean?
another problem is that I want to draw the curve, not just one measure


That's a mixer ferq relation. The max power is always freq1, say LO, the 2nd freq can be RF, so {-1,1} means -1*freq(LO)+1*freq(RF)=IF.
If you can calculate one point power, then you can plot this power vs. freq (RF freq, or IF freq, etc) in the ADS dataset processing window.
 
That's a mixer ferq relation. The max power is always freq1, say LO, the 2nd freq can be RF, so {-1,1} means -1*freq(LO)+1*freq(RF)=IF.
If you can calculate one point power, then you can plot this power vs. freq (RF freq, or IF freq, etc) in the ADS dataset processing window

thanks

but how can I draw curve of gain?
 

You should buy a ADS tutorial for basic knowledge.
 

I can't buy it because our country is boycotted :(

can you introduce another source?


another question, How can I get posotive C.G?
 
Last edited:

there are many methods to calculate the conversion gain in ADS.
1.such as for mixer, see 111.jpg.
2.for data process, see 112.jpg, then edit equation: CG=Mark1-Mark2.
for syntax problem, you can check ads help file.
3. You can also add I probe and V probe, then power is I*V, then edit equation to calculate two power difference.

I want to apply my figure but I ca't
I design a simple gilbert cell but in this circuit the gain is negative. do u know why?
 

Hi every body
I have another question about the mixer
I want to calculate the power consumption of mixer, but I do't know how I can get it

when I replace RF and LO inputs with 50-ohm resistor, current of circuit is decreas (30uA)....and when I don't replace them, I=30mA!!!!
if I change these two inputs or not?
 



why in this example replace them?

You can not terminate the mixer by simply connecting 50 Ohm at each input/output.there will be Dc currents through 50 Ohms..
You should put a DC Blocking element between inputs/outputs and 50 Ohms..
 
You can not terminate the mixer by simply connecting 50 Ohm at each input/output.there will be Dc currents through 50 Ohms..
You should put a DC Blocking element between inputs/outputs and 50 Ohms..

thanks for replying
but how can I measure the power?
 

Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top