Continue to Site

Welcome to EDAboard.com

Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.

[SOLVED] Can I remove tail current of telescopic ota to get larger swing?

Status
Not open for further replies.

fuxinmingming

Member level 1
Joined
Nov 2, 2007
Messages
36
Helped
0
Reputation
0
Reaction score
0
Trophy points
1,286
Location
China
Activity points
1,538
Hi guys,

I designed a telescopic differential ota, its swing is Vdd-5Vdsat, however, it is too small.
Can i remove the tail current and connect the differential pair just to the ground to get larger swing? In that case, the swing becomes Vdd-4Vdsat. What is the defect if I remove the tail current ?

 

If you remove the tail current, you do not have a differential amplifier anymore. If you need a large output swing you should add an output stage or look into a different architecture (for example, folded cascode).
 
Hi Joan,

Since the input signal is differential, the output(output left and output right) also is differential even if I remove the current source.

Since power is another concern, I can't use two stage or folded cascode.
 

Since the input signal is differential, the output(output left and output right) also is differential even if I remove the current source.
In principle, with all ideal components, that is correct but I am afraid it does not work that way. A circuit as you describe it is called "pseudo-differential": it looks differential but it really isn't.
 
Hi Joan,

Can you explain me what's the pseudo-differential in detail ? Why "it looks differential but it really isn't" ?

Regards

Ming
 

With no tail current, the biasing current depends on your input voltages.
Not only do you run the risk of having a large biasing current (if you have large inputs), your small signal parameters are also fully dependent on your input, giving you no linearity and CMRR to talk about.
 
Status
Not open for further replies.

Similar threads

Part and Inventory Search

Welcome to EDABoard.com

Sponsor

Back
Top