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how to plot input impedance in cadence

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venky4u

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cadence impedance

hi
i am implementing active inductor in cadence for that i need to plot the input impedance at various frequencies,so help me about what analysis i need to choose and what are the output variables i need to consider...etc.
iam doing simulations in cadence virtuoso.
please help me out.

its urgent
 

cadence calculator input impedance

Put DC voltage source (V0 for example) connected to to the input with Vdc=Vop, where Vop is operation point of your active inductor. Set AC magnitude to 1mV or 1V.
Run AC analysis. Than using calculator plot VF(V0)/IF(V0). It will plot input impedance vs. frequency.
 
cadence ac input impedance

hi for my inductor i had taken 600mv as operating point voltage and 150mv as ac voltage, when i am using the expression VF(V0)/IF(V0). in my case it is V2 not V0. a messge window is coming.

{evaluation error(ERROR:("eval"36 t nil ("Error"eval :unbound variable"V2)))Expression:VF(V2)/IF(V2)}

one thing i did not understood is why we need to take it as VF instead of V, becoz i dont know the syntax for that.
please clarify it.
 

Frankly speaking you shouldn't type this expression by yourself. Use mouse, calculator window(CW) and schematic window(SW). The steps are as follows:
CW: click VF
SW: click node you are want to put unto CW. The exspression will be apeared in CW
CW: click IF
SW: click device terminal the current of that you want to put into CW. The expression in CW will be changed.
CW: click "/", then click plot.
 

The expression should be like this:
Code: 
VF("/net1")/IF("/V2/PLUS")
where "net1" is the net name to which voltage source "V2" is connected on its terminal "PLUS".
 
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