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Thank you very much to everyone for the explanation. It's very clear to me now.
I do have one more question about it, though. I read the Maxim's website about its advantage over the simple op-amp integrator. It says something about this Deboo integrator can be used with a unipolar supply...
Thanks a lot for your answer. I just looked it up and it's a really interesting circuit. Now I see what the concept behind the design is.
Regarding the impedance question, I think I didn't phase it clearly. The problem states that "this circuit connects a low-impedance source node vi to a...
It is given that the input node vi has low impedance and the output node vo has high impedance. The question is "What does this circuit do?".
Assuming that op-amp's gain is very large, I computed the transfer function and got vo/vi = 2/(s*R2*C), which is an integrator or a low-pass filter...
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