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Sampling exactly at 40Khz will obviously give you better bandwidth efficiency but your tradeoff would be with the filters which will require sharp cutoff
whereas relaxing the cutoff for filter i.e sampling at 44.1KHz will provide a guard band but the tradeoff would be sacrifice of bandwidth
Re: cyclic (7,4) encoder
The encoder used is the one in the third post and extend for fire code with "g(x)=(1+x^5)*(1+x+x^3)=1+x+x^3+x^5+x^6+x^8" and the encoder used with "for loop" did work for (7,4) code ....i was not able to check for (35,27) code.
Encoder: Shifting from right end gives...
Re: cyclic (7,4) encoder
This is in extension with the above program.
Actually if u have idea of fire code which is binary cyclic code....so i have extended the above (7,4) cyclic code for (35,27) Fire code - a 3 burst error correcting capability code...
So the problem is in the below DECODER...
Re: cyclic (7,4) encoder
Hi ....first of all thanks a lot i got the problem solved.....
ya k over here is 4....and i am goin to extend for k=27
however the variable part helped me in the process..and i was able to do it in one clock cycle .....
thnks a lot again....
one more doubt ...i didnt...
Re: cyclic (7,4) encoder
Actually what i was trying to do is encode the input date i.e cyclic encoding where output b contains the input in last k placs( k is length input) and the n-k places contain the parity bits...which i generated by dividing the input by generator polynomial using a...
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