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Can You just solve this :
Suppose we have given a bandwidth of 5000HZ then how do we find the baud rate and bit rate using QAM16 encoding ?
is it 5000 bauds / seconds ?
Still Didn't get it, is frequency and bandwidth are equal ? I don't think so,
Suppose we have given a bandwidth of 5000HZ then how do we find the baud rate and bit rate using QAM16 encoding ?
Bit rate will be
Bit rate= Baud rate * 4
how do we find the baud rate from bandwidth?
is it 5000...
Taken From Google E-book:
In ASK the baud rate is the same as the bandwidth
For PSK the baud rate is the same as the bandwidth
QAM is a
combination of ASK and PSK
If above is true then,
9600 HZ = 96000 Bauds (with ASK)
and
9600 HZ = 96000 Bauds (with PSK)
Then can it be for QAM too...
Don't want to convert baud rate into frequency, I'm trying to say,
Suppose the frequency is: 12000HZ, how do we find the baud rate ?
and I've read all the posts above, and didn't understand, so I decided to register and ask
I know it's already been answered but I'm not getting it.
what will be the baud rate if we have 9600Hz frequency ?
Are frequency and baud rate are inverse of each other?
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