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Re: How to drive cut of frequencu formula for attached LC filter circuit?
Thanks for the feedback. I would like to understand how this formula had been arrived. As i know if it single LC low pass filter then the cut off frequency formula can be derived by equating XL=XC and finally we get...
Re: How to drive cut of frequencu formula for attached LC filter circuit?
I will take output across C1 and C2. In that case could you please guide me how the cut of frequency formula look like ?
Re: How to drive cut of frequencu formula for attached LC filter circuit?
Hello all,
It is kind of redundancy circuit. The output will be taken across C1 and it would be given as input to one switching regulator.In the same way C2 output will be connected to another Switching regulator.
Hence...
Please find my feedback for each question.
Hi,
Please find my
1.Your calculation is correct.But you considered 0.2ohm. That is the requirement from resistor. In my circuit i have 0.15ohm resistor so = 5V/(4096*14*0.15)=0.58mA resolution.
2.It is already developed design and i do not have any...
Hello Team,
I have the existing circuit as like attached and we wanted to interface the solenoid valve with below requirement.
Solenoid Valve current control requirement :
Load current range 0-1.5A
The regulated load current with resolution of 0.78125mA/bit with a 0.2ohm sense resistor...
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