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Recent content by sjb741

  1. S

    Optical smoke chambers

    Am working on a (non-safety crtical, 2nd line of defence) industrial smoke sensor project. We are using an RE46C200 chip and we are at last seeing nice results. However these rely upon a smoke chamber taken from an existing domestic detector. Basically these chambers have to Permit the...
  2. S

    PIC composite (CDC + HID) - failed to modify MLA (MSD+HID)

    Hi Despite opening a case with Microchip, I'm unable to make a composite CDC+HID device work (no matter how simple). Microchip were helpful - but I still have no working solution. they told me "The MCC USB Device Lite library does not support creation of a composite device in an easy way at...
  3. S

    Attenuating piezo sounder for testing purposes

    It has 3 wires. I snipped the ground wire, and now I hear a muted 'buzz' which is acceptable. Physic
  4. S

    Attenuating piezo sounder for testing purposes

    I have a commercial smoke detector which I'd like to use for experimental purposes. It uses a soic-16 chip by "SEMIC": CS2105AGQ-S1Z, TGAY2VU401L. The piezo sounder is the type with 2 terminals (ground, brass and silver <--> ground, drive, feedback ?). If the piezo has a resonant driver...
  5. S

    What mechanism causes Cds photoresistor (LDR) latency?

    Thanks - sounds like the trapped charge is the cause of the asymmetry. Is it roughly true then that trapped charge plays no part in conduction until the mobile charges are used up. Then they diffuse back into the bulk once the bulk carrier concentartion is sufficiently low?
  6. S

    XC8, (45/18) not exactly 2.5?

    Ah, that makes sense, thanks. gRawCount = (0.5 + (45.0/18.0)); //gRawCount = 3
  7. S

    XC8, (45/18) not exactly 2.5?

    //XC8 2.31 volatile uint32_t gRawCount; //Watch result gRawCount = (0.5 + (45/18)); //gRawCount = 2 gRawCount = (0.5 + 2.5); //gRawCount = 3 So (45/18) must have evaluated to a tiny bit under 2.5. I am surprised becasue 0.5 is precisely representable as a...
  8. S

    Op-Amp and resistor network problem

    Hi First, because the stimulus I1 is a DC value, I'll conveniently ignore the effect of C1. V(n002) is then I1*(R2+[R1|R3]) In fact, it is approximately true we can ignore R1 and R3 then we have V(n002) ~= I1*R2 = 1.144 V This is so because of the 'golden rules': The op amp feedback keeps V-...

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