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I'm trying to use two diode-connected MOS transistors to limit the supply voltage (may reach 5.5V) for the 3.3V transistors in 0.13um process.
At normal operation, there is a static current through the diode-connected transistors, making enough voltage drop to keep the circuit safe...
Could you pls tell me your idea? You want to generate a DC voltage (with noise) at node 4? Then use the LM741 to amplify the noise signal?
I think you have to block the DC voltage and add input resistor to the amplifier, otherwise the output of the amplifier will only be the negative supply...
C and D are control nodes, and the one with instance name mark is positive.
You could set the open voltage to 1.6V, and the closed voltage to 1.7V. So when the control voltage is high (3.3V), the switch is turned on.
JUST TRY IT :)
Ok, it seems that shielding is an easier way.
I think there are two circumstances for shielding: 1. to prevent noise lines to disturb other blocks; and 2. to protect sensitive lines from being disturbed. So should I use seperate ground plane for two types of shielding?
The pulse frequency is about 300kHz.
Added after 2 minutes:
If I simply use an inverter to generate the opposite pulse, is the second method still effective? I don't want to make the circuit too complicated.
When I design a drive circuit, I found the wires carrying the pulse signals are quite long and go through some analog blocks. I'm trying to find some method to reduce the potential interference. I have 2 now:
1. Use shielding. But I don't like this method very much, since I worry...
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With a supply voltage of 2.5V, I want to buffer a voltage signal that ranges between 0.25V to 2.25V. I want to know if there exists any simple ways to achieve this. I don't have much current budget on it, and only CMOS devices are available.
Another quesion, do I have to use the folded cascode...