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if you have an unusually high switching frequency and hardly any load current, then perhaps a bead inductor would do.
typical buck regulators utilize inductors that can handle the current and won't saturate.
if this is just a general question, then you are only going to get a general answer...
first - i don't get the point of the diodes. If D1 is forward biased, then it will be attempting to pull current out of the base of Q1 which is an NPN. With D2 forward biased, you're trying to push current into the base of a PNP. What's up with that?
To understand whether this system needs to...
high side mosfet driver
i don't think so, but I can't say for sure - I'd have to see your circuit. The HIP4081 has an internal charge pump that should be able to hold your FET on. I suggest you review the datasheet, especially page 4 under the section titled "Upper Bias Supply Circuit Design"...
This is a suggested topology...
Use 5V as your input voltage. you will need a supply that can support 8 Watts.
Use the EL7532 (datasheet: **broken link removed**) to create a 3.3V rail. Use this rail to power both the Analog and Digital Rails. If you need separation, then use the output of the...
your specifications are fairly broad and very vague. In order to suggest an IC for your application you need to be much more specific. This is what is needed for every rail you want controlled:
Input Voltage, Output Voltage, Output Voltage Tolerance, Max Output Current
You should have no problems with cascading switching regulators, it is done all the time. The only place you may have a problem is if there is an IC with two switching regulators and both of them sharing the same clock. This would cause both regulators to fire the control or synch fet at the...
This is how I would do it:
From the 12V input, create a 5V rail capable of 5A with the Intersil ISL6522 buck regulator.
From the 5V rail, create a 3.3V rail capable of 5.5A with the switching regulator portion of the Intersil HIP6521.
Utilizing the three linear regulator controllers...
I still suggest that you remove the module and apply a 5V supply with an inline resistor/shunt so the load current can be measured. There may be an error in the board layout, there may be poor solder connections, there may be a number of different reasons why what you would expect to be a small...
are you sure that the load is small - have you tried to verify this? Perhaps there is some low impedance fault somewhere that is loading the module down - not enough to cause an overcurrent condition but enough to run it hot.
I would suggest trying to isolate the module on the board such that...
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