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Recent content by LMA

  1. L

    Eigen mode solver of HFSS

    You can calculate the coupling coefficient using the following formula: k=(f2-f1)/sqrt(f1*f2), where f1 and f2 are eigenfrequencies. What is coupling diagram?
  2. L

    Diagonalization of Impedance Matrix

    Just for example. For series RC circuit, [Z] can not be diagonalized at omega=2/(R*C).
  3. L

    Proof of Unequal/Asymmetric Division Through Wilkinson Divider

    The expressions can be obtained using the impedance matching conditions: 1/Z0 = Z0*K/Z02^2 + Z0/K/Z03^2 1/(Z0*K) = 1/R + Z0/Z02^2 K/Z0 = 1/R + Z0/Z03^2 Please note that the expressions for Z02 and Z03 are swapped.
  4. L

    Questions about Radar Cross Section (RCS) simulation in HFSS

    Hello, The incident electric field intensity is given by . "The source has a excitation location and/or zero phase position of 0,0,0" means that r0 = 0,0,0. In the example simulation, Eθ=0 and Eφ=1. Please see also https://en.wikipedia.org/wiki/Spherical_coordinate_system
  5. L

    Equating complex number interms of the other

    The equation can be rearranged as follows: This can help.
  6. L

    HFSS Interpolating vs Discrete Sweep (S11 match but not S21)

    Hi. It may be because the phase of S21 varies much faster than the phase of S11.
  7. L

    Charateristics of {A,B ; C,D} Matrix for lossless circuit

    It is assumed that ABCD-parameters are defined by the following equations: V1 = A*V2 - B*I2, I1 = C*V2 - D*I2. No-loss condition: 0 = real(conj(V1)*I1 + conj(V2)*I2) = real(conj(A*V2 - B*I2)*(C*V2 - D*I2) + conj(V2)*I2) = real(conj(A)*C*conj(V2)*V2) + real(conj(B)*D*conj(I2)*I2) + real((1 -...

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