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Yes, thank you but I knew that one. However they do not mention any frequency in this problem.
But I appreciate your response. I believe the next response from Akanimo is what I was missing. But really, thank you so much for replying.
I’m very lost with this problem. I thought I knew this stuff. This is a exercise problem.
What is the value XL in the circuit. The absolute value of Es is 100V. It says, first find Z, noting E and I are given. Next Find X, then XL.
Where does X come in? I’m just drawing a blank on this one.
Yes, I guess its this arbitrary current direction that confuses me. I mean what you say is right because the all currents do = 0. I have to look at this again and wrap my head around it. Thanks for the swift reply.
LeatherNeck.
What bothers me here is that node P2 has all the sense arrows pointing into the node. I would have figured at least one would leaving the node. This is pertaining to exercise #4. I mean actually it works out. But should’nt one arrow point leaving the node?
Oh my god. Thank you. I see it. No one at work could help me. Again my eyes were closed. They simply wanted to get it into a more useful form. I just couldn’t see it. Wow. Thanks again.
RiF = hib/(Ro/RF) = RF/(Ro/hib)
I don’t see how the hib gets in the very bottom in this equation.
I will attach an image of the page this comes from. I can see that
Ro/RF gets inverted, but I would have kept hib in the numerator.
Thanks, that is the answer. I mistakenly included the (-) in my calculation. So actually here is what I was doing,
2.2,0deg - .15,170deg. I put in -.15 but should have been just a positive vector. Man o man. Sometimes.
thank you so much for the help. I had my eyes closed. :)
Hello everyone. I am trying to do a polar to rectangular conversion on my simple Casio fx-260 and it gives an error. Here is the Polar
-0.15, 170degrees. No matter how I state the angle, it gives and error. Any clue’s?
Yes, I am familiar with this technique. I have done that with the PWM output of an Arduino micro to modulate intensity of an LED. You are correct, the output of our circuit has a big power transistor mounted on a sizable heat sink.
Ok that all makes perfect sense to me. I did look at the data sheet and, yes very small GBP. So the intent of the designer was to use a 35 watt halogen light to simulate the flame inside a gas or oil burner. Using this white noise signal summed with a DC level to mimic flame flicker. Another...
Ok, I changed the 330k to 100k voltage divider and increased the feedback resistors to 100k and 10k with a 10uF cap to ground on R34. It is actually amplifying the signal now. There is 100mV of signal out now. Should I keep trying to increase the gain of the stage? White noise is different...
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