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I want to design a synchronous counter with 12 states and synchronous reset by connecting the overflow signal ( CT =15 ) directly to load input ( /M2M1 ) so that I can start the counter at a custom state, what I'm thinking of doing right now is just put flip-flops pre-loaded with my predefined...
You make it sound like it's true for only H(s) = 1 when it works for all H(s). If G(s) = (s+2)(s+9) and H(s) = 1/(s+6), then
OL poles = -9,-6
OL zeros = -2
Root locus of CL system will travel from [ -9 and -6 ] to [ -2 and \[\pm\]Infinity ], H(s) just changes the path the locus will take...
Isn't that how closed loop poles travel, how does the root locus of G(s) = (s+2)(s+9) look like?
Consider this, lets assume my plot is correct, if i wanted to find the value of K at the point s = -3 in the root locus plot, I would use the formula
\[ k = \frac{\prod |s - p_i| }{ \prod | s -...
I meant to write characteristic Equation ( GH(s) ) = 0 instead of just GH(s) = 0.
Lets take a simple example of G = (s+2)/(s+9) , H = 1.
Open Loop Pole = -9
Open loop Zero = -2
The root locus of the closed loop equation ( G/(1 + GH) ) will thus be a straight line travelling from -9 to...
The way I understand it is that in order to solve 1 + KGH(s) = 0, you first solve GH(s) = 0 which will give you the open loop poles, those are the poles were the root locus plot will begin ( ie the poles for K=0 )
Or you can consider the fact that in root locus plots the value of K can be found...
Consider a standard feedback control system with controller gain K(s) and plant transfer function G(s) with unity negative feedback( ie H(s) = 1 ).
The characteristic equation of the system is 1 + KGH(s) = 1 + K(s)G(s).
Now when finding the root locus you find the poles and zeros at K=0 ( Open...
I don't really understand what you are trying to do, are you trying to derive one clock from another one? e.g you have a 20MHz clock and you are trying to derive a 5Hz clock from it so you can use the 20Mhz clock to power one component and the 5Hz clock to power another.If this is what you are...
I have modules that define a parameter N, I also have an encapsulating module that instantiates all the other modules and it also defines the parameter N, so the problem I'm having is that every time I want to change the value of N I have to go into all the modules one by one and change N's...
How do I set an output high for the future clock cycle in system verilog.I would really want this module to only consist of one code block.
Eg. I have one input signal A, and two output signals B and C, if A = 0, I want B to go High in the next clock cycle but if A = 1, I want B to go high in...
Yeah, I guess it was a loading problem, I increased the R1 and R2 resistors in the common collector amplifier to values over 100k and Re to 5k and the circuit simulated well.
The output drops at the output of the amp when I connect the buffer to the end of the amplifier in simulation, I have not connected a load to the end of the buffer yet.
Ce = 10microF
Test_Freq = 1Khz
The output drops at the output of the first stage.
Vin(AC) = 0.1v peak to peak
Vout(Stage...
But I need to pick the Re2 value carefully because it will help me better choose the capacitor Ce properly, I want to make sure I have all my components designed properly.Right now the values I've given together with a Re2 value of 3.9K give me a small signal gain of 6.7 when I simulate them on...
Isn't the DC gain the one that is - (R1/R2)? The gain Av refers to the AC gain that you get that from small signal analysis, Av = - gm * ( R1 || RL ).
Where gm = 40Ic
I know, AC gain = Rc/Re1 = 6
Re1 and Re2 will determine the bias point but I first need to pick a suitable value for Re2, and for that I will need to use KVL going around the output loop, and for that I need to get VCE.
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