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Recent content by kakar133

  1. K

    [SOLVED] Dipole Array Simulation in 4NEC2

    I am using Surface patches as a ground plane to increase directivity in particular direction.
  2. K

    [SOLVED] Dipole Array Simulation in 4NEC2

    Hello Everyone; I am trying to simulate dipole array in 4nec2. There are two identical configurations for arrays. In one configuration I put dipole array parallel to a ground plane (4 elements at y=0,x=3x1 and 4 elements at x=0, y=3y1). While in second configuration I used same array with only...
  3. K

    [SOLVED] Dipole Array (two element Array) Simulation in 4NEC2

    Dear All, I am trying to simulate dipole array in 4nec2, but i am not getting correct results for patterns. e.g for two element array with lambda/4 spacing between them and 90 degree phase difference, I should get a cardiac shape pattern but I could not get. I have attached expected pattern...
  4. K

    Perfect ground with finite dimension in 4NEC2

    I want to add perfect ground plane below array but with finite dimension so that gain can increase. Also, i tried the same problem with array above infinite pec and i got the required plot which is attached. why i can not simulate ground plane with finite dimension. ?
  5. K

    Perfect ground with finite dimension in 4NEC2

    The distance between the ground plane and array is lambda/10; between the array element it is lambda/2. I should get one main lobe with two side lobe. you can see the current distribution on the element and pattern. I excited all of the elements with one volt and zero phase. - - - Updated -...
  6. K

    Perfect ground with finite dimension in 4NEC2

    Hello every one. I am trying to design a dipole array parallel to a finite ground plane in 4NEC2. but i did not find any option to set the dimension of ground plane in NEC, Instead I made grid of wires to substitute for ground plane but it is not working in a correct way. Please can some guide...
  7. K

    ADS 2011 layout problem for Wilkinson Power Divider

    no i have not connected the left side with the right side. it is generated by the ads. If i remove the resister then it gives correct layout,but without resistor it is not going to work please help me.
  8. K

    ADS 2011 layout problem for Wilkinson Power Divider

    Dear all, I have design a wilkinson power divider in ADS2011. i am getting correct result for S parameters. but the problem is with layout. I am not getting correct layout. please look at my layout and tell me what is the problem.
  9. K

    How to design Microwave Filters , Power Dividers or Couplers Design?

    re: How to design Microwave Filters , Power Dividers or Couplers Design In Divid Pozar's book, he has given an example for equal split Wilkinson Power. In the graph S11and S23 seems to be below than -40db.where as S12 is about -3.5db. Can I get the same graph in ADS for these parameters at...
  10. K

    How to design Microwave Filters , Power Dividers or Couplers Design?

    re: How to design Microwave Filters , Power Dividers or Couplers Design I want to design wilkinson power divider at 1 Ghz or 1.5 Ghz. I do not understand the purpose of frequency in design.Also, what should be the typical values of insertion loss, return loss and isolation that are attainable...
  11. K

    How to find the induced current on the sphere ?

    Can some one help me about this question.I shall be very thankful. A conducting sphere of radius a is centered at the origin. A plane wave in the direction(theta, phi) illuminates this sphere and causes induced currents on it. the polarization of plane wave is (a_phi). find the induced current...
  12. K

    How to design Microwave Filters , Power Dividers or Couplers Design?

    Dear All, I am new to microwave engineering. I want to design microwave filter or power divider or coupler in a same course(Microwave Engineering). I need guidance from experienced members of the forum regarding design. I have some questions. Can someone guide me about these Questions. 1) What...
  13. K

    Location of at Equilibrium

    Thank you very much.
  14. K

    Location of at Equilibrium

    Q2/2=4*Q2/[(-x-1)2*2] ? how you obtained this step from the previous one , I mean (-x-1)^2. In the previous step it was (x-1)^2.
  15. K

    Location of at Equilibrium

    it means that both Q2 and Q3 are at the same position.

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