Welcome to our site! EDAboard.com is an international Electronics Discussion Forum focused on EDA software, circuits, schematics, books, theory, papers, asic, pld, 8051, DSP, Network, RF, Analog Design, PCB, Service Manuals... and a whole lot more! To participate you need to register. Registration is free. Click here to register now.
I'm having problems simplifying this boolean logic using the basic laws and theorems with proof.
AB'(C+D)+(C+D)'
The answer should be AB' + C'D', but how is this result reached? Can someone show me the steps and alegebraic theorems used.
All I have is
AB'C + AB'D + C'D'[/code]
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.