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Recent content by ironmanzzy

  1. I

    the formulas about isertion loss of coupled resonator filter

    hi, some professor how can i get the following formulas, the insertion loss of the single resonator:L(f)=-10log{(1+(2QL*(f-f0)/f0)^2)/(1-(QL/QU)^2)}; the insertion loss of the filter: L(f)=-10log{((1+QE/QU)^2/2kQE+kQE/2)^2+2((1+QE/QU)^2/k^2-QE^2)((f-f0)/f0)^2+4((QE/k)^2((f-f0)/f0)^4}...
  2. I

    How to get the following fomulas?

    the insertion loss of the single resonator:L(f)=-10log{(1+(2QL*(f-f0)/f0)^2)/(1-(QL/QU)^2)}; the insertion loss of the filter: L(f)=-10log{((1+QE/QU)^2/2kQE+kQE/2)^2+2((1+QE/QU)^2/k^2-QE^2)((f-f0)/f0)^2+4((QE/k)^2((f-f0)/f0)^4}

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