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Hi Dale,
Yes, Vin peak would be 20√2 = 28.28V if the efficiency of your H-bridge were 100%.
But you said you have an estimated efficiency of 65%, so you'll have to increase Vin(DC) to 43.5V to compensate for this inefficiency.
In other words, you'll be supplying more than 3000W to get 2000W...
Hi Dale,
Your values for load (output) current and voltage are RMS, so
Pout = Iout • Vout
Pin = Iin • Vin
But the input current is equal to the output current (there's no current leakage in your H-bridge, just resistive losses) so
Iin = Iout --> Pout = Iin • Vout;
Given that...
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