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dear Tanmay, kindly read my above comment before you reply anything, as i have written that if ack error and crc error detected on the same frame then error frame will be generated due to ack error because it is mentioned in can part A and part B document (please refer page 25 under error...
no need to use any mux just simply connect gsm modem to mcu i/o pins and by using carry bit recieve every bit and by using appropriate delay u can recieve the data without using the tx and rx pin.
dear emb4u, sir you are right due to different speed crc in both side will not match and crc error will generate , but also ack error will generate and the error frame will generate only due to ack error not for crc error , as per datasheet when a crc error occurs then the error flag will...
i am doing can communication using at89s8252,mcp2515,pca82c250..actually i donot have any can tool to visualize the bits and i have a doubt that there are how many bits in active error frame and passive error frame. please suggest and explain .also please suggest how a node on can bus...
dear, embd4u, as per your answer i think mcp2515 handles the busoff condition and its not an overhead for mcu to reset the can controller . so we can say that mcp2515 is having self reset ..right..?..please suggest
typedef facility allows us to define a new nam for an existing data type...... here in the above expression When this exception handler function is called, the parameter Data pointer contains the same value as you provided when you registered the handler.
hi , i am doing can communication using mcp2515 can controller,at89s8252 mcu and pca82c250 can transceiver... i have a doubt regarding the speed of nodes....if we have two nodes with different speed (bit rate ) on a can bus ..then what will happen will the communication happen smoothly or any...
how it is possible that two data frames will be on bus till complete tx.....that means if two nodes are trying to access one same node by sending their data frames (both the data frames are identical as i said above) ..then the 3rd node will receive both the frames ...how is it possible...
dear ftsolution , sir actually i asked that if two node are with same identifier that is the address of device as u said and the data field are same that means two identical data frames ...it means they have equal number of dominant and recessive bits then how the arbitration will occurre and...
so who will loose arbitration and how....because as i said that both the frame having same bits upto the data field means the identifier and datas are same how the arbitration occures please explain it sir..........
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