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Confidence level is a statistical term that defines the probability that the outcome that your model predicts is actually true. Generally, the confidence level that you select will determine the sample size required in your model.
The circuit should work but as Klaus pointed out your simulation scale is wrong. C17 will take 5 seconds to charge through your 1M load. Only once C17 is charged will you see a voltage drop across it since it is a short to the high frequencies that you are measuring. The 0.9V that you see is the...
In theory ESR doesn't vary with frequency. It is a DC resistance in series with the ideal capacitance. So, you must calculate the ESR at 120Hz which is how the D.F. is specified. Xc will vary with frequency, but the ESR is still "ideally" the same - 159mR.
Could you rephrase the question to something that explains what kind of help that you want?
Your message conflicts with the diagram that you supplied.
The gate will get Vbat but the diagram shows Vbat going to the drain.
Source will be tied to ground - no its not in the diagram, it is tied to...
For anyone still interested, I found an old ATX power supply using the same circuit for the +5VSB. So, I disabled all the unrelated circuitries including the feedback that stabilizes the +5VSB. It works! 12.4V out with no load. The output is unstable with a load but nonetheless works and...
Actually, I now see how this is supposed to oscillate. Because of the low C1 value I thought it was oscillating at mains frequency. But probably this won't work with this type of transformer. This is actually a modified schematic from an old ATX power supply's +5V standby circuit except that...
First of all, the emitter is not shorted to ground ( hot ground that is ). There is a 12 ohm emitter resister. But you are essentially correct. The C1 capacitor is discharging 320V through a 12ohm resister when Q1 turns on. I guess at least 25A(peek) through Q1. 1N4007 diodes in the bridge are...
Note that a limitation of the Superposition Theorem is that it must involve all linear devices:
You should not use superposition theorem for this because diodes are non-linear devices. However, since both diodes are on in this case and the diodes are ideal diodes with no voltage drop, it will...
There are many power transistors. You need to know also know npn or pnp, Vce, Hfe required, bandwidth or switching time needed, etc...
In general, I use the MJE3055T or variant for generic power transistor application of more than 1A for npn circuits. Make sure to use appropriate heat sink with...
Did you ever have one of those puzzles made of a bunch of little squares with one hole? You had to solve the puzzle by moving the squares around. The hole was there to allow you to move the squares into it.
Was the hole moving?
First of all, the Vce(sat) is not constant at 0.2V - it varies with the base current.
Secondly, anything above 0V is forward biased, 0.7V is roughly the knee voltage for silicon pn junction to turn on. You are confusing forward bias with turn on voltage. For ex: if BE is forward biased at 0.7V...
There is insufficient information to solve this problem: you need to know either L or C so that you can solve the winding resistance of the coil.
From there, you can Thevenize the equivalent parallel resistance of the tank circuit. Then calculate the new Q and BW with the load Thevenized.
As is...
The Anthropic Principle
We use Quartz because it has the property of a high Q which is an ideal property for an oscillator. Otherwise we would look for a better material with a higher Q.
Effectively, the high Q is a result of the narrow bandwidth of the resonant frequency at which Quartz...
Thevinizing is meant for linear circuits. So you cannot accommodate the functionality of the ADC circuit since it is non-linear.
However, you could Thevenize the input of the ADC. It would simply be the input impedance of the ADC.
You could also Thevenize the outputs for given states if they are...
The base of the transistor will be clipped by the base-emitter junction of the transistor so the input of the inverter will NEVER go high. It will be limitted to around 0.8V ( depending slightly on the current).
You need a resistor so that the base of the transistor can be at 0.7V while the...
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