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The question is at this link IIT 2005 Main Paper Physics : IIT JEE 2005 Physics Main Question Paper and Solutions . Since the solution cannot uploaded i print screen my solution and uploaded at this 2 website **broken link removed** and **broken link removed** . I would like to ask for opinion...
hmm, may be you are right but i just considering the case for a pure resistor network a heater(load resistance) and a internal resistance connected in series. Lets say i put different load resistance, load A may be giving me an efficiency of X and output power of Z, load B may be giving an...
As i mention above if putting load resistance which is very large, the efficiency of course will reach almost 100% but the output power is extremely small. I just considering in finding a suitable load resistance value that will give optimization in power saving and output power. Using this...
In Thevenin maximum power transfer theorem it state that the load resistance,RL must be equal to internal resistance of the source,Rin. However, the efficiency of the circuit is just 50%. At here, can i say i use power source in a more effective way if be able to have an output of higher...
May i know if take an idea of someone circuit undergo modifying process become a new product out(different function) still consider as circuit design or nothing different like plagarism.... and the first person to design the circuit is know as inventer?
A cylinder is closed at both ends and has insulating walls. It is divided into two compartments by a perfectly insulating partition that is perpendicular to the axis of the cylinder. Each compartment contains 1 mol of oxygen, which behave as an ideal gas withγ=7/5. Initially the two compartments...
Oh ok. Thank you very much that is something new i learned today:D. From a reference book i read, i only saw how the author derive the formula for capacitor. It say V=V1+V2 where V1 and V2 is the voltage across the capacitor so V=Q/C
than Q/C=Q1/V1+Q2/V2 than since it is series Q1=Q2=Q also...
hmm sorry for making the above mistake, i confuse it with parallel capacitor calculation. In series capacitor, the charge store in C1=C2 correct? I guess what
dedalus mention is correct. Thank you dedalus.By the way, I can only figure that for figure 1 charge store in capacitor C1 minus charge...
Let assume V3>V1 and V3>V2 also. The both equation also correct however the equation 2 does not show conservation of charge. When V3>V1 and V3>V2 is obvious V3>Vd1>V1 and V3>Vd2>V2 also. Vd1-V3 will result in a negative value. However if we consider the total charge store in the capacitor we do...
This is a simple overload protection circuit in a power supply. Usually that configuration(the differential opamp and diode) is use to control the power supply whether function in current mode or voltage mode(refer to 2nd attachment). However, i modified it become an overload protection...
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