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I have two curves
1) gm/Id at Y-axis and voltage sweep at X-axis.
2) Vov at Y-axis and voltage sweep at X-axis.
Now I want gm/Id at Y-axis and Vov at X-axis.
Can anyone help me as how to do it?
Thanks
-Bharat
At high frequency poly resistor exhibits capacitive nature. If the foundry has BSR blocked salicide resistor, better use it as it has almost zero temp coeff.
an rc circuit in parallel solution
Thanks drabos for the reply
Yes its true to intuitvely think about these circuits, therefore I avoided any laplace transformation type of approach. But sometimes in intricate R and C combination it becomes difficult.
On digging it further, I came across OTC (...
No, am not asking the answer. I want the analysis in time domain.
Like in simple low pass filter, R is charging the C and time const is RC.
If one more R is in parallel to C, taking the Thevinin eqv. the Rth will be R/2 and Vth will be V/2. Now, R/2 will charge same C by V/2 voltage so time...
stabble rc circuit
I understand that standard RC low pass and high pass circuits are discussed in many text books.
One we discuss the variant of the same as adding R in parallel to C or C in parallel to R, I am not sure of answer in time domain.
As I mentioned, I don't want LT solution because...
All,
I am not clear in solving such types of questions which are usually asked in the interview-
1) unit step input given to RC circuit
2) what if another R is added in parallel to R
3) what if R is added in parallel to C
4) instead of unit step if a pulse is given when the swing is -V to V...
All,
I am not clear in solving such types of questions which are usually asked in the interview-
1) unit step input given to RC circuit
2) what if another R is added in parallel to R
3) what if R is added in parallel to C
4) instead of unit step if a pulse is given when the swing is -V to V...
lvds driver output resistance
Hi,
If the outputs of differential signals are padp and padn, which are giving 350mV peak, the resistance between padp and padn should be 100ohms.
If your CMFB impedance is much higher vlaue, try making it 100 ohms resistance between the two outputs.
Thanks
-Bharat
v_c and pmonon,
I am very much involved in the ongoing discussion being the original poster.
I am rephrasing my doubt " Capacitor resists any instantaneous change across its plates"
In the light of above; Think of resistor divider circuit and replace the resistances with equal capacitances...
Hi,
I want to know the Lenz's law equivalent in electrostatics.
To elaborate the same:
The inductor resist any instantaneous change of current across it and can easily be modeled by replacing the inductor with voltage source to continue the current to flow in same direction. This is in line...
difference between decade and octave
Normalised gain is 20 log (w1/w2). If the ratio of w1:w2 is 1:2 then the expression can be represented as 20 log (1/2) = -20 log 2 = -20X0.30103 = -6dB per octave
If w1:w2 is 1:10 , then the same expression 20 log (1/10)
= -20dB per decade
-Bharat
The o/p impedance does vary with with Vds ( because of CLM). Try to increase the channel length to 3x of min channel length of the technology. This will make the lambda lesser (lambda is inversely proportional to channel length). Lesser the lambda, lesser the variation due to Vds. I understand...
Choosing the larger dimension of diff pair may help in reducing offset values or use offset cancellation techniques.
hi tekno1,
Why are you referring back bias here? Is it not any finite value of Vsb (source to bulk) but it will be same for the both nmos diff pairs?
Also, what is impact...
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