Half bridge smps transformer turns calculation.

  1. codemaster11
    codemaster11
    dear, i calculated the numbers of turns for a half bridge smps using EI33a core

    http://tahmidmc.blogspot.com/2013/02...lation_22.html

    according to me minimum input Vin(min) = 100*1.414 = 141Vdc

    N(prim) = (141*0.5*100000000)/(4*50000*1.3*1500) = 18 turns


    at minimum voltage duty cycle will be max, duty cycle = 0.98, at max duty cycle average voltage to transformer

    vin(min) = 141Vdc

    duty cycle = 98%

    desired output voltage Vsec = 22 volt

    average voltage to xformer (Vprim) = 0.98*0.5*141 = 69.29 volts

    the ratio (Vpri/Vsec) = 69.29/22 = 3.15, that's equal to turns ratio (Nprim/Nsec) = N = 3.15.

    here Nprim = 18 turns, Nsec = Nprim/N = 18/3.15 = 5.7 turns

    for auxiliary Vaux = 18 volts, auxiliary voltage to (secondary voltage + diode drop) N = Vaux/(Vsec + vd) =

    18/(22+0.5) = 0.8


    Naux = Nsec/N = 5.7/0.8 = 4.6 turns.

    here another video https://www.youtube.com/watch?v=TLD6hUV64YU&t=10s

    who calculate turns for half bridge xformer, i 'm confused here who one is correct?

    because he take the half of full 311Vdc while calculating Nprim also used another method for finding Nsec & Naux?

    can someone help me regarding this calculation whether it is correct or not ?
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