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Since as we increase temperature we are actualy increasing the kinetic energies of the atoms so the will strike with a greater force on the walls of the container in which they are held and as volume is inversly proprtional to the 1/v so it will decrease hope it will help.
But why do you want to consider temperature increase with Boyle's Law? Or perhaps we could consider it macroscopically (fal_con has done the microscopic interpretation) you could rephrase your question as such: say you have a graph of 1/V on x-axis, and P on y.
T is proportional to PV. So when P increases, V will decrease since T is constant. When V decreases, 1/V increases. So P increases with 1/V. Hope this would help you.
we have only to consider the Boyle's Law formula..in which PV (product of pressure and volume) as constant..the Law doesn't consider the increase in temperature so no need to think that one..We have the law to follow..remember Boyle's Law only consider the pressure and the volume..
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