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Suppose your first four bits are 1110 in your bitstream. The output of the desired circuit will be 3. Now you have done input ==1. Here the input remains 1 for the first three bits. So in this case you will count 1 instead of 3.
Can you please reply interms of architectures rather than codes?
Well.. you could use the data signal as a mask for the clock by logically ANDing your data signal with the clock and use the resulting signal as a "clock" for a counter. So, when the data signal is '1', the clock will pass (in your case, three '1's'), but when the data signal is low, it will mask the clock and provide no output, hence, the counter will not count up.
if you have no clock validates bits or do not know the bit rate
[to create the clock on board]
there is no way to distinguish between a series of [let's say] two 1's
coming with 20MHz and ten 1's with 100MHz;
at least I don't know how this can be done;
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It was my assumption that you were clocking in data to begin with, so I would just use that clock. If it is just a random signal with no clock associated with it, then I have no idea how you would do it as you need some frame of reference to begin with.
In case of asynchronous signals, I believe it is OK to count number of positive going edges of the input signal in order to count the number of ones (i.e. number of times the input goes high).
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