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how to improve the parr of a bandgap

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zxasqw123

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i can not understand why big L can improve the PSRR of a bandgap?
and Does the psrr depend mainly on the opamp?
thank you for advance
 

can you be more specific ? Large L on which device(s) in the circuit?
 

Large L of which transistor??
 

Generally, large L or cascode structure can improve PSRR. Because both of them lead to higher output resistance, which makes drain current more stable when there is Vds variation.
 

large L , cascode structure , decrease the current, increase the Av of the errorAmp
 

Large L negates the effects of channel length modulation which would otherwise spoil the basic idea of having equal currents in both the BJTs.
 

Large L can improve the mos which in bias circuit mismatch insensitive
 

due to larger L the lamda effect will reduce hecnce the output resistance will increase and the circuit will be more robust for the any noise r any variation of VDD hence greater PSRR ..
hope this helps.
 

Large L and decrease Gm of the currrent mirror and reduce the gain of power noise.
 

In my opinion, bandgap psrr is mainly depended on the structure which you choose. Secondly, the op amp is also important, refine its propery ,you can acquire more high psrr for the bandgap.
 

I think large L will increase the output impedance and loop gain. Higher loop gain means higher PSRR.
 

Can I use a voltage regulator before a bandgap to further inprove PSRR? In this case, it create a loops between bandgap and voltage regulator, where bandgap supply reference voltage to regulator. Anyone have experience in this?

Regards.
 

Large L means
1. lambda effect lower
2. o/p res Rds of tr is higher
Basically u need higher resistance. U can do by decreasing W also but the lambda effect gets decreased by big L. So anther adv
 

large Ls make CS like more ideal CS
cascode CS shield output and power supply from miller effect.
 

with large L, the ro of transistor is also big
 

Using Cascode, check the attachement
 

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