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A question about Razavi's book

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qiushidaren

qiushidaren

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I am analyzing the circuit in problem 2.6(c) of Razavi's book "Design of Analog CMOS Integrated Circuits", but I am confused about the conclusion in the solution manual, it says that the device turns off when Vx=2-Vth+R1I1.
But I think that once Vx is larger than 2-Vth, the device will always in saturation region, can someone explain this to me, whether the solution manual is wrong or I am wrong?
Thank you in advance!
 

I think the solution manual is right.Because the souce of M1 is becoming high as the Vx,and when it is up to 2-Vth,M1 will turn off, the current of Vx will flow into R1 which is equal to I1.At that time,the Vx=2-Vth+R1I1.
So do I.
Rgds,
longstar
 

longstar said:
I think the solution manual is right.Because the souce of M1 is becoming high as the Vx,and when it is up to 2-Vth,M1 will turn off, the current of Vx will flow into R1 which is equal to I1.At that time,the Vx=2-Vth+R1I1.
So do I.
Rgds,
longstar
Click to expand...
Thanks for your reply and explanation.
 

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