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22nd March 2006, 19:13 #1
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Interview Q
hi,
hw to implement 4:1 mux and 2:1 mux as Nor gate?
ple reply soon its urgent.
thanks in advance.
bye,
Prasad

22nd March 2006, 19:13

23rd March 2006, 08:49 #2
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Re: Interview Q
2 x 1 MUX, make the equation first:
O = (EN & A)  (ENb & B)
then make it logic gates
finally replace to NOR gates

23rd March 2006, 08:49

23rd March 2006, 10:57 #3
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Re: Interview Q
Check the document

23rd March 2006, 10:57

24th March 2006, 10:37 #4
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Re: Interview Q
For a 2 input nor gate,there are 4 possible combinations,so we can implement it using 4 x 1 multiplexer.The two inputs A and B are given to the mux as selection inputs and keeping enable signal high.
Now for 2 input nor gate the output will be 1 when all inputs are 0.,thus we will connect Vcc to I0 and ground to I1,I2 and I3.

25th March 2006, 13:23 #5
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Re: Interview Q
I have drawn the diagram for nor gate by using 2 X 1 MUX

25th March 2006, 13:23

5th March 2007, 12:43 #6
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Re: Interview Q
hi,
Nor using 4×1 mux, suppose A,B are select lines. Y is output.
I0,I1,I2,I3 are input to mux.
Give VDD to I0,
GND to I1,I2,I3.
Nor using 2×1 mux,
I0,I1 are input to mux,
Take A as select line.
Give complement of B to I0 input of Mux.
Gnd to I1 input of Mux.
Checkfunctionality.
Hop u understand.
If u hav any doubts tell me.

5th March 2007, 12:57 #7
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Interview Q
Hi p_shinde
Look what a nor gate does.Assume A and B are inputs.
If B zero it passes the (A complement) to output.
if B is one then output is '0'.
Now connect B to select
A' to LSB input
and logic 1 to MSB input
Regards
tronix
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