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[Question] Technology scaling and power consumption

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hebu

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If two identical digital core circuits, which are, implemented in 0.18um
and 0.13um, respectively. What's the power consumption relation between
the two implementations?

Any rule of thumb or simple calculation?

Thanks,
 

you can reference
Digital Integrated Circuits A
Design Perspective(Senond Edition)
 

It's said P=a*C*V²*f.

a= activity factor
C= capacitance
V= supply voltage
f= operating clock frequency

For 0.18um case

C=0.18^2
V=1.8^2

For 0.18um case

C=0.13^2
V=1.3^2


(C*V²_0.18um)/(C*V²_0.13um)=3.67

So, the power consumption of 0.18um is 3.67 times the consumption of 0.13um?

If it's the case, the improvement by proecess technology is huge.
 

yes, for the same circuit, the improvement is huge,
normally, as process scaling, the design is more and more complex. so we can see that the power of the intel's CPU is more and more high.
by the way, P=a*C*V²*f is only dynamic power
as for other kinds of power, such as leakage power, it maybe higher as the process scaling, because leakage current will increase, under 0.13um, leakage current is a serious problem
 

Leakage power must be paid more attention in .13 and below tech. In the same design in the same nano level tech, different percent of hvt or svt cell used in the design may result in different power consumption.
 

suituse said:
Leakage power must be paid more attention in .13 and below tech. In the same design in the same nano level tech, different percent of hvt or svt cell used in the design may result in different power consumption.


Compared to 0.18um process, how serious the leakage of 0.13um?
More specifically, What's the ratio of leakage in total power consumption?

Any estimation method?

Thanks,
 

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