Member level 3
is it illegal to use 'z' value in expression, in synthesis point of view?
and in any form inside a clocked always block?
7th June 2005, 15:45
Full Member level 3
z in verilog
Not entirely true ... U can synthesise 'casez ' to produce a priority mux structure . Z indicates undriven state so don't make any calculations based on these ..
8th June 2005, 08:29
verilog z value
if u have a Z state in mux it will not work.....
8th June 2005, 11:18
Full Member level 6
Z should not be used in internal logic,
because internal tri state gate can increase chip's power consumption and
increase difficulty to DFT. Z only can be used on top IO ports.
Originally Posted by Prasanna Kumar
verillog equating z
What about U (Un-initialized) value of VHDL when converting to verilog.
I have some troubles with VHDL files with 'U' when converting to Verilog.
Does someone have a solution?