+ Post New Thread

Results 1 to 2 of 2

- 2nd December 2016, 14:47 #1

- Join Date
- Sep 2016
- Posts
- 12
- Helped
- 0 / 0
- Points
- 110
- Level
- 1

## signal received by a node j in wsn

Hi all,

I want to know what is the formula of received signal by node j separed by distance d from a source i in wsn.

sometimes I find this formula: yij=hij * x+nij

in another yij=sqrt(p * gamma)* hij*x+nij ; where p is the source transmit power and gamma is the pathloss

another formula is yij=sqrt(p) * hij * x+nij ; where p is the source transmit power

I'm confused please can someone help me , thanks.

- 2nd December 2016, 14:47

- 16th December 2016, 15:11 #2

- Join Date
- Jan 2011
- Posts
- 410
- Helped
- 44 / 44
- Points
- 2,896
- Level
- 12

## Re: signal received by a node j in wsn

They are all valid for analysis purposes. Usually, if you say that x has normalized power, then you include sqrt(p), such that the signal-to-noise ratio (SNR) is P/N, where N is the noise power. Some like to make it more practical by including the pathloss, but I think unless the analysis is about the pathloss, and shadowing effect, it's not necessary to be included. It's just a scaled factor in RF channels.

+ Post New Thread

Please login