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Step up booster IC Help

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gauravkothari23

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HI all....
I need some help regarding STEP-UP Booster IC.
i am working on a application where i have to interface SST89E516RD2 and GSM module with Voltage Source from Li-Io batteries voltage range 3v to 4.2V. The battery has a maximum output current of 2.2Amp.
My problem is My controller works on 5V for which i am using step up ic TPS61032-5V to power my controller.
but my GSM module SIM-800 works on 4v. for which i again have to install a second step up IC TPS61030-Adj to power my GSM module. Infact i can connect my GSM module directly with the battery, but i need the system to work till the battery voltage reaches 3.0, in which my GSM module wont work. so i have to add an step up IC to power my GSM module seperately, so that the even GSM Module works with the battery voltage of 3v.
current consumption of my controller is hardly 200 m-amps, but the GSM module consumes around 1.8Amps of current when sending and receiving message.
So can anybody please guide me, if i can use two seperate IC's to power two different components as per their voltage requirement or can you suggest me any single IC where i can power both with their respective voltage, or using two different IC's would be a better choice in this case.
Thanks.
 

The battery has a maximum output current of 2.2Amp.
...
the GSM module consumes around 1.8Amps of current when sending and receiving message.

This leaves small margin to drive additional devices. You'll drain even more power by stepping up the voltage to drive those devices. Can you be sure that battery voltage will maintain?

Perhaps your job is simpler if you put two batteries in series?
 

you mean to say... Battery voltage to be at 8.4v and then use a step down converter.
Actually in my appliation i need a longer battery life. so for that i am using 2 samsung li-io 2600mah batteries in parallel to get about 5200 mah of life. but now even when i have 3.7v 5200mA of battery i am not able to supply current more than 2.2mA of current becuase of protection circuit. but now if i place this batteries in series, the supply voltage will be around 8.4v 2600mA. so in such case i wont be able to supply 2A of current.
 

By adding an LC filter at the input, you can step up Amperes while stepping down voltage.



Notice the supply voltage (6V). Therefore the buck converter can work even when your batteries are nearly drained.

Notice the output current is greater than the supply current. Notice that a smooth current waveform is drawn from the supply.

It would pay for you to try simulations of all the options available. Did you simulate a boost converter? With a range of supply voltages (down to 3V)?. See what amount of Amperes you must draw, to power your devices.
 

By adding an LC filter at the input, you can step up Amperes while stepping down voltage.



Notice the supply voltage (6V). Therefore the buck converter can work even when your batteries are nearly drained.

Notice the output current is greater than the supply current. Notice that a smooth current waveform is drawn from the supply.

It would pay for you to try simulations of all the options available. Did you simulate a boost converter? With a range of supply voltages (down to 3V)?. See what amount of Amperes you must draw, to power your devices.

Thanks a lot,
I think using a step down would be a better choice for me...
but i did not understood some part of your circuit.
what is 50m at input and 2.5 at output.
what is CLK... is it a switch.
what diode should i use.. can i use 1n5819.
the circuit you showed is for 5v output, what changes should be done to get a output of 4v for my GSM module.
 

By adding an LC filter at the input, you can step up Amperes while stepping down voltage.

Notice the supply voltage (6V). Therefore the buck converter can work even when your batteries are nearly drained.

Notice the output current is greater than the supply current. Notice that a smooth current waveform is drawn from the supply.

It would pay for you to try simulations of all the options available. Did you simulate a boost converter? With a range of supply voltages (down to 3V)?. See what amount of Amperes you must draw, to power your devices.

i tried the circuit as you said...
the output i get is something different.
i am not able to step down the voltage.
 

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Hi,

Hope it's okay to answer the simple questions...
50 milliohm and 2.5 Ohm resistors.
CLK is clock, you could make one with a transistor/MOSFET and an astable oscillator (maybe just an astable 555?) at the 3KHz frequency Brad's simulation shows.
Schottky diodes seem to be used for SMPS as they are fast and lower voltage drop than rectifier diodes.
For 4V you'd need to calculate the inductor and capacitor values and clock frequency, based on a Buck converter's formulas.
 

I agree with D123's reply.

The 50 mOhm resistor is not needed. It is there to indicate some amount of unknown resistance in the power supply.

The clock is a pulse generator. It opens and closes a switch. The simulator makes it look simple (overly simple). In hardware you would install a transistor/mosfet in the same location.
 

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