Jester
Full Member level 6
LED being used: https://www.mouser.com/ds/2/311/GW JDSRS1.EC - DURIS E 5 (EnglishDeutsch)-520766.pdf
This LED has an exposed thermal pad, if I'm interpreting the data sheet correctly θJ to pad is 26°C/Watt.
If I use the maximum current rating of the LED of 180ma, then Pd=3 * 0.18 = 0.54W
Using the TI app. note below, rule of thumb of 2.37 in² per Watt, I would need 1.2 in² for 40° rise, this assumes double sided copper.
I read the following to determine how much PCB copper is required https://www.ti.com/lit/an/snva419c/snva419c.pdf
Hopefully this is correct so far?
Now what if the board has conformal coating?
This LED has an exposed thermal pad, if I'm interpreting the data sheet correctly θJ to pad is 26°C/Watt.
If I use the maximum current rating of the LED of 180ma, then Pd=3 * 0.18 = 0.54W
Using the TI app. note below, rule of thumb of 2.37 in² per Watt, I would need 1.2 in² for 40° rise, this assumes double sided copper.
I read the following to determine how much PCB copper is required https://www.ti.com/lit/an/snva419c/snva419c.pdf
Hopefully this is correct so far?
Now what if the board has conformal coating?