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[SOLVED] Triode region equation

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preethi19

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Hi i am reading a paper "+ 1V high frequency four quadrant current multiplier"
It operates in triode region and i know the eqn for triode region is Id= K [(Vgs-Vt)Vds - (vds^2)/2]
triode.png

Mp and Mn are in triode and Mc is in saturation..
i am able to understand that Vds in the paper is (Vin +VDD) and Vt is Vtp. But for Vgs why is it 2VDD and why not just VDD??? can anyone kindly explain!!! Thank you!!!
 

preethi19 said:
i am able to understand that Vds in the paper is (Vin +VDD) and Vt is Vtp. But for Vgs why is it 2VDD and why not just VDD??? can anyone kindly explain!!! Thank you!!!
Click to expand...

Vgs=Vg-Vs
MOS "Mp" : Vg=VSS and Vs=VDD => Vg-Vs=-2*VDD
MOS "Mn": Vg=VDD and Vs=VSS => Vg-Vs=2*VDD
 
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