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This network has three independent loops and three independent nodes. You will have to do the classical three simultaneous equations and solve for the current from the battery. Then R=E/I
just find the node voltage of the 2 circuits and add them together. once you know the voltages of all the nodes, then you can find the current across each resistor and also your final input total resistance.
This makes things difficult. I am certain I have never seen an oddball resistor network such as this in any schematics. Anyways, a good approximation for your circuit is to calculate the voltages without the cross resistor. Then you will get 7.5 on one side and 5 on the other.
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