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Common ended LC filter for 100 watts inverter

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fadhel93

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Hello

I am working on a project of a 100 watts pure sine wave inverter, using DC to DC converter (push-Pull topology) as a supply for the H bridge (from 24 to 80 V ), the H bridge is controlled using mbed microcontroller. everything works fine till I connect the LC filter it draws large amount current without any load.
switching frequency=16KHz

Can anyone help me please.

123.JPG

321.JPG

schematic circuit for the H-bridge and mbed
 

Your LC arrangement could be called a second order butterworth filter. It should be designed to resonate at a higher frequency than your switching frequency. However it is possible the two frequencies are close together.

It is essential that a load be present across the capacitor. With no load, you may expect it to draw enormous current.

A similar problem comes up with audio amplifiers, if you were to install a similar type of 2nd-order low-pass filter. Suppose you disconnect the speaker. Then play a sound which is the resonant frequency for your series LC. It will draw extreme current, with the risk of burning up components in the power amplifier.
 

thank you,
"It should be designed to resonate at a higher frequency than your switching frequency." why?

The cutoff frequency for the filter is -1/2pisqrt(LC)- about 300Hz.

If I connect ceramic capacitors rather than non-polorized Electrolytic Capacitor , it did not draw current .
 

thank you,
"It should be designed to resonate at a higher frequency than your switching frequency." why?

Apologies for my error. I meant to say fundamental frequency.

Assuming your fundamental is 50 or 60 Hz, then you wish to filter out all higher frequencies. It is reasonable to set a rolloff frequency for 80-100 Hz.

The LC values need to be custom selected, to pass sufficient current for your load, while shaping the waveform into a sine.
 

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