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Matlab. Not enough input arguments?

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patrick.r

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Code: 
function y=draft(x)
C=25200;
B=-242.5;
R=3101.122;
y=(x^3)/C + (x^2)/B + x/R - 1;
x0=3101.122;
solution = fzero(draft,x0);

in line 5 that defines y, the error says that there are not enough input arguments. I've even tried a know code that should have worked but gave me the same error any insight would be helpful on how to fix it
 
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Once you are performing matricial division, I presume you should use the "./" operator instead the "/".
 

andre_teprom said:
Once you are performing matricial division, I presume you should use the "./" operator instead the "/".
Click to expand...

In his case i don't think his variables are matrices,they are scalars.But both('/' & './') should work,i guess.

@patrick.r
Your error - there are not enough input arguments.

I think you are not giving value of 'x' to your function. Try using the function,say as draft(100.25) in command window.It should work provided function is added to your path/in working directory.
 

Not only division operator, but also the power operator "^" must be in matrix format ".^":

Code: 
y=(x.^3)./C + (x.^2)./B + x./R - 1
 

patrick.r said:
Code: 
function y=draft(x)
C=25200;
B=-242.5;
R=3101.122;
y=(x^3)/C + (x^2)/B + x/R - 1;
x0=3101.122;
solution = fzero(draft,x0);

in line 5 that defines y, the error says that there are not enough input arguments. I've even tried a know code that should have worked but gave me the same error any insight would be helpful on how to fix it
Click to expand...


Code: 
function [ y ] = draft(x)
%UNTITLED2 Summary of this function goes here
%   Detailed explanation goes here

C=25200;
B=-242.5;
R=3101.122;
y=(x^3)/C + (x^2)/B + x/R - 1;
x0=3101.122;
function z = example(x0)
   z = fzero(draft,x0);
end
end
^ This will work along with my post 3.But i'm now trying on how to display the value of fzero function to command window as well.will reply back.

@andre_teprom:
Both('/' & './') & ('^'& '.^')should work.They are scalar variables
 

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