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[Moved] Speed from motor in rpm

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Vimala04

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can you plz explain the flow of this code?


Code Verilog - [expand]
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module(clk,mpulse,speed);
input clk,mpulse;
output[15:0]speed;
wire [15:0]speed;
reg[31:0]cval, tcount, quot,rem;
reg zero,sts;
wire rfd;
assign speed = (zero?16'd0:quot[15:0]);
always@(posedge clk)
begin
if(!mpulse && sts)
begin
tcount = cval;
sts = 1'b0;
cval = 32'd0;
zero = 1'b0;
end
 
else begin
if(mpulse)
sts = 1'b1;
if(cval = 32'd4000000)
zero = 1'b1;
else
cval = cval+32'd1;
end
end
spddiv speeddiv(.dividend(32'd120000000), .divisor(tcount), .quot(quot, .rem(rem), .clk(clk), .rfd(rfd));
endmodule
 
Last edited by a moderator:

It looks like you are trying to determine the speed by using the relation speed=distance/time. That is the reason you are using a divider block. Looks like the distance is fixed (1200000). But haven't gone into the details. You will need to simulate it and find out
 

Speed from motor in rpm

Thank you for giving solution
 

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