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format specifier problem in c-language

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v.s.n.kumar

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Hi,
can anybody tell what is the result of below lines in c.
main()
{
int i=0x90;
printf("%%d",i);
}
 

if you use 2 % in printf in output you have %d. so your output is %d. but if use printf("%d",i) output is 144 decimal of 90 hex.
 

I know that the result is %d. but what is the reason for giving as %d
 

you should use one %. because % is for formatting and every time that compiler see %,it looks for formatting option, for example d or f. and if you want to print % character, you should use %%.
 

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