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Biased PN Junction Basics

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Kunal Pattanayak

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in the basic circuit diagram of a biased pn junction connected at both ends by a battery, we say that an electric field is set up equivalent to the RESULTANT of the electric field because of the charge depleted region, and because of the battery.Can anyone tell me hoe is the kirchoffs voltage law being followed in this case.(As far as i can see, one round of the ckt. doesnt result in the net drop being zero)
 

Kunal Pattanayak said:
in the basic circuit diagram of a biased pn junction connected at both ends by a battery
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If the pn junction (a diode) is forward biased and does not have a series current limiting resistor then the current will be as very high (as much as the battery can supply) and the diode and battery might blow up or catch on fire!

If the diode is reverse biased then the current is just extremely low leakage current.
 

well it hardly matters what the repercussions might be, but i basically want to know WHY its said(taught) that the electric field inside the depletion region is a resultant of the field from the barrier potential AND the field resulting from the battery.
 

I use diodes and transistors, I do not design and make them so I never think of electric fields and depletion regions inside them.
The datasheet for a diode or transistor tells you every thing you need to know about it to use it correctly.

I guess your teacher wants you to know how to design and make a diode or transistor.
 

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