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BJT diode connected load

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sarge

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Hi, i'm trying to calculate small signal gain for common emitter amplifier with bjt diode connection load.
For diode connected bjt resistance is equal to parallel connection of Rbe and current source b*Ib. Rbe much smaller then Rcs and therefore Requal ~ Rbe.
For gain we have A = -gm1*Rbe2

Am i right?

Update: Sorry, i said stupid thing, resistance of diode connected load is the Re. But anywhere i still can't calculate small signal gain. Re = Vt/I = 1/gm - same as in mos device. A = gm1/gm2 = (I/Vt)/(I/Vt=1 ^(
Where did i made mistake?
 
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