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  1. #1
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    Relationship between carrier frequency and the bandwidth of the system?

    I have some basic doubts in communication. I got this while I was reading about Optical Communication. It states that "The higher the carrier frequency, higher is the bandwidth of the system."

    How can you say that?

    Also

    It states that optical communication has higher bandwidth when compared to normal communication using RF.

    Plz help me with this confusion

    Thanks a lot :)

    •   Alt17th November 2012, 08:41

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    Re: Relationship between carrier frequency and the bandwidth of the system?

    I don't agree with that publication. Bandwidth of RF or optical communication depends on the type and frequencies of the modulation used. An unmodulated carrier, at any frequency, has no bandwidth.



    •   Alt17th November 2012, 11:50

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    Re: Relationship between carrier frequency and the bandwidth of the system?

    It would make more sense if instead: "The higher the carrier frequency, higher is the bandwidth of the system." it said "The higher the modulating frequency, higher is the bandwidth of the system."

    Optical communication has higher bandwidth simply because there is more "space" in frequency spectrum. In optical domain you are using frequencies of order 10^14 Hz compared to RF frequencies, let's say 10^6 - 10^9 Hz



    •   Alt17th November 2012, 12:41

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  4. #4
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    Re: Relationship between carrier frequency and the bandwidth of the system?

    Optical communication has higher bandwidth simply because there is more "space" in frequency spectrum.
    Yes, I think the original post is asking about this trivial fact. More exactly, we should say: potentially higher bandwidth, if the modulation method allows it.



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    Re: Relationship between carrier frequency and the bandwidth of the system?

    In terms of data communications bandwidth is bits/sec that the system can transmit.
    I think that a higher carrier can be modulated by a higher frequency and thus achieving more symbol rate. So the statement is true. The frequency bandwidth occupied by the channel will be wider.

    Please disregard my previous post.
    Last edited by albert22; 23rd November 2012 at 02:36.



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