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[SOLVED] Phase reverse in diode balanced mixer

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anhnha

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Hi everyone,

Could you help me explain why UthD1 and UthD2 have phase reverse?
I read this equations from a book but it is not give me a detailed explaination about it.
UthD1 = Uth cos(ωth.t)
UthD2 = Uth cos(ωth.t + π )
UnsD1 = UnsD2 = Uns
i tg1 = I tg1 cos(ωns – ωth)t
i tg1 = -I tg2 cos[(ωns – ωth)t + π ] = -I tg2 cos(ωns – ωth)t
where UthD1 is the voltage of signal dropping in D1 diode
UthD2 is the voltage of signal dropping in D2 diode
Thanks a lot.
 

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Re: Diode balanced mixer

D1 & D2 are connected on opposite legs of the trafo on the left. Hence the opposite phase.
What else did you not understand ?
 
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    anhnha

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Re: Diode balanced mixer

D1 & D2 are connected on opposite legs of the trafo on the left. Hence the opposite phase.
What else did you not understand ?

Thanks so much.
Now I got it.I am so careless.
 

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